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| Elections in Alabama |
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The 1860 United States presidential election in Alabama took place on November 6, 1860, as part of the 1860 United States presidential election. Alabama voters chose nine representatives, or electors, to the Electoral College, who voted for president and vice president.
Alabama was won by the 14th Vice President of the United States John Breckenridge (SD–Kentucky), running with Senator Joseph Lane, with 54.00% of the popular vote, against Senator John Bell (CU–Tennessee), running with the Governor of Massachusetts Edward Everett, with 30.89% of the popular vote and the 15th Senator Stephen A. Douglas (D–Illinois), running with 41st Governor of Georgia Herschel V. Johnson, with 15.11% of the popular vote.
Republican Party candidate Abraham Lincoln was not on the ballot in the state. It would not participate in the 1864 election, which Lincoln won.
Douglas's 15.11% was the lowest vote share ever for a Democratic presidential candidate in Alabama. The combined 84.99% of the vote between Breckinridge and Bell was the highest third-party vote share in a presidential election in Alabama ever.
Douglas was the first Democrat to lose Monroe County since 1852, and Choctaw, Dallas, Marengo, Sumter and Wilcox Counties since 1848. Additionally, Douglas was the first Democratic nominee ever to lose the following counties: Clarke, Jackson, Limestone, Morgan, Washington.
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Southern Democratic | John C. Breckinridge | 48,669 | 54.00% | |
| Constitutional Union | John Bell | 27,835 | 30.89% | |
| Democratic | Stephen A. Douglas | 13,618 | 15.11% | |
| Total votes | 90,122 | 100.00% | ||

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